Help Please!!

#1
1.Given f(-1) = 0.15, f(1) = 0.29, f(3) = 0.21, and f(5) = 0.35, find P(X ≤ 1)

2.Given f(-1) = 0.15, f(1) = 0.29, f(3) = 0.21, and f(5) = 0.35, find F(1)

3.Given f(-1) = 0.15, f(1) = 0.29, f(3) = 0.21, and f(5) = 0.35, find P(-1 < X ≤ 3)

and the rest using this distribution function
F(x) = [0 for x < 1; 1/3 for 1 <= x < 4; 1/2 for 4 <= x < 6; 5/6 for 6 <= x < 10; 1 for x >= 10]

4.find P(2 ≤ X < 6)

5.find P(X = 5)

6.find P(X ≤ 6)

I know this is a lot, but help is really needed and I would be much appreciative!
 

JohnM

TS Contributor
#2
What are you not understanding about this?

1.Given f(-1) = 0.15, f(1) = 0.29, f(3) = 0.21, and f(5) = 0.35, find P(X ≤ 1)

here, the answer is 0.29 + 0.15 = 0.44

With F(x), it is a cumulative function, so you need to realize that F(x) is the probability of x and anything less than x.