Does anyone have any idea how id show this?

Thanks!

- Thread starter JP712111
- Start date

Does anyone have any idea how id show this?

Thanks!

Also you mentioned a professional opinion as the 'correct value'. I think you might be interested in two things, the training's impact on getting closer to the professionals opinion, and reduction in the variation between people after training.

It’s on a scale of 1-9 so say a cat is a 6, the owner before advice guesses 4 but after advice they guess 7. I’d want to prove statistically that when advice is given, the owners are “better able” to body condition score (in the sense that the difference between (post advice - vets guess) is less than (pre advice - vets).

I thought I could do two non paired t tests and then state the variance and standard deviation?

Null: Advice has no impact on a persons ability to score a cat closer to the Vet's score.

Depending on how many data points you have, you might be able to construct a contingency table and perform a Persons Chi-squared. The way I would set this up in on one axis I would groups the difference between the unadvised score and the vet into 0,1,2,3+ and on the other axis the difference between the advised score and the vets score into the same 0,1,2,3+ to create yourself a 4x4 contingency table.

Do you have a statistical software package? R, MiniTab, SPSS, SAS. If not you can do this pretty easily in excel. The only caution with this test is when you don't have a lot of data, the page has some details on it. Good luck and let me know if you have any other questions.

The way I would set this up in on one axis I would groups the difference between the unadvised score and the vet into 0,1,2,3+ and on the other axis the difference between the advised score and the vets score into the same 0,1,2,3+

i.e. if you assume that the difference between levels 4 and 3 is the same as

between 8 or 7, or that the difference between levels 8 and 6 is the same as

between 3 and 1. In that case, one could just calculate the individual absolute

differences before training and after training, respectively, and compare them

using t-test for dependent observations, or the Wilcoxon signed rank test.

With kind regards

Karabiner

i.e. if you assume that the difference between levels 4 and 3 is the same as

between 8 or 7, or that the difference between levels 8 and 6 is the same as

between 3 and 1. In that case, one could just calculate the individual absolute

differences before training and after training, respectively, and compare them

using t-test for dependent observations, or the Wilcoxon signed rank test.

With kind regards

Karabiner

Your dependent variable is the difference between owner's rating and the veterinary's rating? You have measured this for the very same owners at two time points? Therefore, an analysis for dependent measures is appropriate.

With kind regards

Karabiner

With kind regards

Karabiner

Ive done paired t tests for the differences before and after training and obtained a value but doesnt this just tell me the relationship between each other and not in relation to the vets score? So it would tell me that the two data sets are different from each other but without a comparison to the vets score it would be pointless? (the attached pictures are of t tests i had performed, one pic of a paired t tests between the two values and another pic comparing the differences to the vets (which i had made 0))

Sorry to seem like a pain but to me making two independent t tests i can then go on to say the t stat value for pre advice is > than t stat value after advice showing weak agreement that giving advice helps reduce difference, but im not sure if im explaining this right to even my academic tutor who is also a bit confused

Thank you to all who have helped

You need to create two sets of a data(100 observations each) which are the difference between the person's score and the vet. Lets U = untrained score, T = trained Score, and V = vet Score. Your Null hypothesis is |U-V| = |T-V| ; you are wanting to know the absolute difference and are not caring about the direction.

It looks like you are using excel, if you want to attach it, and erase any personal information like medical numbers, names, dates of birth, etc. I can set up a new tab with notes.

You need to create two sets of a data(100 observations each) which are the difference between the person's score and the vet. Lets U = untrained score, T = trained Score, and V = vet Score. Your Null hypothesis is |U-V| = |T-V| ; you are wanting to know the absolute difference and are not caring about the direction.

It looks like you are using excel, if you want to attach it, and erase any personal information like medical numbers, names, dates of birth, etc. I can set up a new tab with notes.

Please find attached the excel file- if you could reply also with an explanation so i actually know what on earth im looking at! Have a meeting with my tutor about this on wednesday so need to look like i know what im doing!

Ive attached the file and made two more columns with the difference between (Pre advice and vet) and (Post advice and vet). These values are with ABS formula just so you know, again like you said the absolute difference and not caring about negative or positive.

(Talkstats doesnt let me attach excel file so just attached the dropbox link to download) - If you could reply to my email address with the new tab and or any stats formulas then it would be amazing. My email address is jay_p1997@hotmail.co.uk

https://www.dropbox.com/s/rwu74kxv9552uw0/Trial12.xlsx?dl=0

Any help will be appreciated. Many thanks