For example, suppose these 6 teams have these records against the rest of the league, which includes 30-40 other teams. Assume that each of these teams have played each of the other teams more or less the same number of times.

Code:

```
[FONT=Courier New]Team Wins Games %[/FONT]
[FONT=Courier New] A 40 50 80.00%[/FONT]
[FONT=Courier New] B 30 50 60.00%[/FONT]
[FONT=Courier New] C 25 50 50.00%[/FONT]
[FONT=Courier New] D 20 50 40.00%[/FONT]
[FONT=Courier New] E 10 50 20.00%[/FONT]
[FONT=Courier New] F 0 50 0.00%[/FONT]
```

If P(x,y) is the probability that Team X will beat Team Y, where x & y are the winning percentages from the table above, then P should have the following properties:

- 0 <= P <= 1
- P(x,x) = 0.50 (Two teams with the same record should have 50% odds against each other.
- P(x,y) + P(y,x) = 1 (The complementary probabilities should sum to 1.)
- P(x,0.5) = x (Since Team X's record is against the entire league and the average of all the wins and losses for all of the teams in 50%, if Team X plays a team with a record of 50%, it should be like playing the entire league, which is what its record is. I am not sure about this one,m but it seems right to me.)

Two that I tried are:

- P(x,y) = (x-y+1)/2
- P(x,y) = x/(x+y)