Hello

I have trouble on making the hypothesis test(especially making a Null hypothesis), I have tried all the calculating process but still confuse about choosing a Null statement.In more details, I don't understand the word "test the hypothesis for mean"

Assuming the population standard deviation is unknown, our sample size is n=31 so by CLT it is normally distributed, the question is :

"By selecting the same significance level(α=0.05) which you used in report 2 (for building confidence intervals) test the hypothesis for mean for both (independent and dependent) the variables by doing the following:

· State the null and alternative hypothesis for independent and dependent variables,

· Find the test statistic.

· Determine critical value or p-value,

· Find the decision, conclusion, possible error

· Explain the meaning of this error in the context of the problem, and how to minimize this error."

The research I Choose is to research about the relationship between the time of self-study and academic performance in Business Statistics among RMIT students in Hanoi campus.

By survey, I have the 2 dependent and independent variables data are :

Time (minutes)

180

120

180

180

300

40

60

120

60

0

320

30

120

120

90

400

30

480

200

90

135

180

180

200

200

150

30

150

260

900

30

Score

14

17.5

16

16

14.75

17

14

20

12.5

16

16.5

13

14

19

11

16

16

15

16

15

15

15.5

15.5

14.5

16.5

15

16

14.5

17.5

19

11.5

The lecturer said that I can do the test without getting T or Z value from calculating regression and 1 tail or 2 tails is on my own, and for the mean of the population(μ) I could choose what ever from the interval range of 114.89 ≤μ≤ 242.21(time) and 14.74 ≤μ≤ 16.21(score) to do the test

further data :

Mean:178.5483871

Standard Error:31.17001036

Median:150

Mode:180

Standard Deviation:173.5472729

Sample Variance:30118.65591

Kurtosis:9.520116329

Skewness:2.67114606

Range:900

Minimum:0

Maximum:900

Sum:5535

Count:31

Confidence Level(95.0%):63.65765361

Lower Value

178.5483871 - 63.65765361 = 114.8907335

Higher Value

178.5483871 + 63.65765361 = 242.2060407

Mean:15.47580645

Standard Error:0.360024424

Median:15.5

Mode:16

Standard Deviation:2.004531157

Sample Variance:4.018145161

Kurtosis:0.591533637

Skewness:-0.012927699

Range:9

Minimum:11

Maximum:20

Sum:479.75

Count:31

Confidence Level(95.0%):0.735267965

Lower Value

15.47580645 - 0.735267965 = 14.74053849

Higher Value

15.47580645 + 0.735267965 = 16.21107442

Please Help me, thanks you.

I have trouble on making the hypothesis test(especially making a Null hypothesis), I have tried all the calculating process but still confuse about choosing a Null statement.In more details, I don't understand the word "test the hypothesis for mean"

Assuming the population standard deviation is unknown, our sample size is n=31 so by CLT it is normally distributed, the question is :

"By selecting the same significance level(α=0.05) which you used in report 2 (for building confidence intervals) test the hypothesis for mean for both (independent and dependent) the variables by doing the following:

· State the null and alternative hypothesis for independent and dependent variables,

· Find the test statistic.

· Determine critical value or p-value,

· Find the decision, conclusion, possible error

· Explain the meaning of this error in the context of the problem, and how to minimize this error."

The research I Choose is to research about the relationship between the time of self-study and academic performance in Business Statistics among RMIT students in Hanoi campus.

By survey, I have the 2 dependent and independent variables data are :

Time (minutes)

180

120

180

180

300

40

60

120

60

0

320

30

120

120

90

400

30

480

200

90

135

180

180

200

200

150

30

150

260

900

30

Score

14

17.5

16

16

14.75

17

14

20

12.5

16

16.5

13

14

19

11

16

16

15

16

15

15

15.5

15.5

14.5

16.5

15

16

14.5

17.5

19

11.5

The lecturer said that I can do the test without getting T or Z value from calculating regression and 1 tail or 2 tails is on my own, and for the mean of the population(μ) I could choose what ever from the interval range of 114.89 ≤μ≤ 242.21(time) and 14.74 ≤μ≤ 16.21(score) to do the test

further data :

**Time**Mean:178.5483871

Standard Error:31.17001036

Median:150

Mode:180

Standard Deviation:173.5472729

Sample Variance:30118.65591

Kurtosis:9.520116329

Skewness:2.67114606

Range:900

Minimum:0

Maximum:900

Sum:5535

Count:31

Confidence Level(95.0%):63.65765361

Lower Value

178.5483871 - 63.65765361 = 114.8907335

Higher Value

178.5483871 + 63.65765361 = 242.2060407

**Score**Mean:15.47580645

Standard Error:0.360024424

Median:15.5

Mode:16

Standard Deviation:2.004531157

Sample Variance:4.018145161

Kurtosis:0.591533637

Skewness:-0.012927699

Range:9

Minimum:11

Maximum:20

Sum:479.75

Count:31

Confidence Level(95.0%):0.735267965

Lower Value

15.47580645 - 0.735267965 = 14.74053849

Higher Value

15.47580645 + 0.735267965 = 16.21107442

Please Help me, thanks you.

Last edited: