First post here so please accept my apologies if this question was posted before.

This is baffling me for quite a few days now and I can't figure out a way to calculate it.

What I know: Successive tosses are independent; knowing we got H on the first toss does not help us predict the outcome of the second toss

Each trial has the same probability P(H)=1=2=P(T)

What I can't figure out is this question: Knowing each Time you toss a coin it is independent of the previous toss, lets say you toss the coin 5 times and it comes (For Example: HTTTH) what is the probability of I toss the coin 5 times again and it comes exactly HTTTH ? what about 6 times? what about 7? so on and so forth... I believe there is some sort of factorial involved in this but I am not 100% sure.

a formula with some explanation would be greatly appreciated as I can't wrap my head around this... seems very simple but I am not too good at this.