TI83 - p-values for less than t test two sample differ by .002 when applying 1-[two-tailed-p-value]
So I thought that a less than p value is equal to 1-[two-tailed-p-value] but on a TI83, I see that this is not the case. The reason I need to know is I am trying to make my own calculator using Apache commons math3 library, their function for a t test gives me a two tailed answer and I also need left and right tailed given that answer.
Below shows what I typed into the calculator and what came out.
On TI83:
x_bar_1 = 9.678571428
Sx1=2.94459418
n1 = 28
x_bar_2 = 6.857142857
Sx2 = 3.86546231
n2 = 28
Not Pooled
For p-value, ≠ is .0034193612
For P-value, < is .9982903194
If the equation was right, (1-[two tailed p value] = less than p), the p value would be .9965806388.
Question:
Is the TI 83 correct?
If it is what equation do I apply in order to find the other two p values?
So I thought that a less than p value is equal to 1-[two-tailed-p-value] but on a TI83, I see that this is not the case. The reason I need to know is I am trying to make my own calculator using Apache commons math3 library, their function for a t test gives me a two tailed answer and I also need left and right tailed given that answer.
Below shows what I typed into the calculator and what came out.
On TI83:
x_bar_1 = 9.678571428
Sx1=2.94459418
n1 = 28
x_bar_2 = 6.857142857
Sx2 = 3.86546231
n2 = 28
Not Pooled
For p-value, ≠ is .0034193612
For P-value, < is .9982903194
If the equation was right, (1-[two tailed p value] = less than p), the p value would be .9965806388.
Question:
Is the TI 83 correct?
If it is what equation do I apply in order to find the other two p values?
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