Poisson distribution question

WeeG

TS Contributor
#1
hi guys, I seem to forgot how it's done, a little help will be appreciated !

the number of accidents in a factory have the Poisson distribution with a mean of 2.0225 accidents a day.

a. what is the probability that during 3 working days in a row, the general number of accidents will be 2 or bigger than 2 ?
b. calculate the probability that in a working week of 5 days, there will be exactly 3 days with maximum of 1 accident.

cheers !
 

vinux

Dark Knight
#2
Hint:
a. if X1,X2,X3 are Poisson rv. with mean lambda, then X1+X2+X3 follows Poisson with mean 3*lambda
b. p= Probability of maximum of 1 accident=P(X <=1). then use Binomial distribution