- Thread starter shawnteh1711
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You have it in the wrong way ...

The definition of accumulate distribution is p(X≤x)

p(X>x)=1-p(X≤x)

Now if you know the population's standard deviation, you can calculate the average's standard deviation,

And the mean of the average is the mean of the population.

The confidence interval is a range that the random variable will be in a probability of the confidence level.

For example, if the confidence level is 0.95, the probability that the random variable will be in the confidence range is 0.95.

You have it in the wrong way ...

The definition of accumulate distribution is p(X≤x)

p(X>x)=1-p(X≤x)

Now if you know the population's standard deviation, you can calculate the average's standard deviation,

And the mean of the average is the mean of the population.

The confidence interval is a range that the random variable will be in a probability of the confidence level.

For example, if the confidence level is 0.95, the probability that the random variable will be in the confidence range is 0.95.

Yes, of course , I just imagined a more complex question like "what is the probability that X̄ is greate than the right range confidence interval ...

So Shawneth, just look on a normal chart and tell us, what is the probability that a normally distributed variable will be greater than the mean? (as the mean of the average is also the mean of the population ...)

So Shawneth, just look on a normal chart and tell us, what is the probability that a normally distributed variable will be greater than the mean? (as the mean of the average is also the mean of the population ...)

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So Shawneth, just look on a normal chart and tell us, what is the probability that a normally distributed variable will be greater than the mean? (as the mean of the average is also the mean of the population ...)