Probability question

svs

New Member
This is a problem from the book Statistics for Experimenters by Box, Hunter, Box book, page 151.
For each sample of 16 boxes of cereal an average box weight is recorded. Past records indicate that on the average 1 out of 40 of these average box weights exceeds 8.4 ounces and 1 out of 40 is less than 8.1 ounces. What is the prob that an individual box of cereal selected at random will weight less than 8 ounces?

Does my solution make sense?
Pr(x>8.4ozs) = 1/40=0.025
Pr(x<8.1ozs) = 1/40=0.025
z value associated with pr 0.025 is 1.96
therefore, Pr(x<8.0) for 1 of 16 boxes at random is df = 15, ...and now i am getting confused. Please help. Thanks.

Devanil

New Member
Well, observe that average box weight (W) is approximately normal with mean 8.25 and sd=3/3.92=0.765. So, P[W<8]=P[Z<(8-8.25)/0.765]=P[Z=-3.267]=0.0006.

Last edited:

Devanil

New Member
Uooops. observe that average box weight (W) is approximately normal with mean 8.25 and sd=0.3/3.92=0.0765. So, P[W<8]=P[Z<(8-8.25)/0.0765]=P[Z<-3.267]=0.0006