Sum of squares model proof

A0063377

New Member
Hello everyone

I'm trying my best to prove the formula for the sum of squares model (please excuse how badly i'm going to write this)

Betahat'X'Y-n(ybar)squared

so far i have that it is equal to (yhat-ybar)'(yhat-ybar) so i just need to show that they equal eachother.

I know that both yhat transpose and yhat = X(X'X)-1X'
It just isn't working out for me at all and if i could get some help I would be extremely extremely grateful

Englund

TS Contributor
Is it correct that you want to prove that

$$b'X'y-n\bar{y}^2=(y-\bar{y})'(y-\bar{y})$$?