....is infinite countable or uncountable?

Dason Ambassador to the humans Oct 12, 2013 #2 Oct 12, 2013 #2 Well since [math]\sigma^2 I_{nxn}[/math] is a valid covariance matrix for any [math]\sigma^2 \in \mathbb{R}[/math] the answer is uncountable.

Well since [math]\sigma^2 I_{nxn}[/math] is a valid covariance matrix for any [math]\sigma^2 \in \mathbb{R}[/math] the answer is uncountable.