for uniform dist. f(y) = 1/(6-2)= 1/4. So I tried integrating that from 0 to 2.5, but it didn't work. I think I'm missing something, but I can't put my finger on it. Please help!

- Thread starter megs915
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for uniform dist. f(y) = 1/(6-2)= 1/4. So I tried integrating that from 0 to 2.5, but it didn't work. I think I'm missing something, but I can't put my finger on it. Please help!

quark said:

Hi megs915,

The customer needs to wait for the elevator, then it would take 15 sec to get to 1st floor.

2.5 min=150sec, so he needs to wait for 150-15=135sec

The uniform distribution ranges from 120sec to 360 sec. Thus the probability is :

(135-120)/(600-120)

The customer needs to wait for the elevator, then it would take 15 sec to get to 1st floor.

2.5 min=150sec, so he needs to wait for 150-15=135sec

The uniform distribution ranges from 120sec to 360 sec. Thus the probability is :

(135-120)/(600-120)

If the uniform distribution of waiting time ranges from 2 to 6 minutes, we add 15 seconds to it, to get 2.25 to 6.25, which includes waiting time plus travel time (for 1 floor in this case).

Then the probability of getting from the 2nd floor to the 1st floor in 2.5 minutes (or less) would be:

(2.5 - 2.25) / (6.25 - 2.25) = 0.25/4 = 1/16 = 0.0625