Combinations average

I have 6 averages, 365, 406, 420, 416, 434, 435. How many ways can you split the group to have two groups of 3 with similar averages? The closer the average, the better. Each average can only be in one group.


TS Contributor
This will depend on how similar should similar groups be to be considered similar :)? You have C(6,2) =6!/4!*2!=15 different groupings, the similarity in each should be easy to calculate.