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I've been given a question that I don't understand.
Question: Consider a test which rejects H0 if the number of observed successes is ≥r≥r , where r is some number. What is the smallest value of r that gives a test of size not exceeding 0.05?
We have been given:
o=50 ,for 50 observations
H0=p=1/2
I know that a test size is the probability of committing a type 1 error, where we falsely reject the null hypothesis when the null hypothesis is true. This happens 5% of the time if our p-value cut off is 0.05.
What I'm not sure about is : "What is the smallest value of r that gives a test of size not exceeding 0.05?"
Because if r is just some random number that hasn't been specified, what's stopping me from putting in a large number for r , such as 49?
I've attempted it by using:
mu=np
SD=sqrt(np(1−p))
a=0.05
Using RStudios for computation I did the following:
qnorm(0.95,mean=50*0.5,sd=sqrt(50*0.5*0.5)
But this gives me the test value. Because i'm unsure about what the question means, i'm not sure if this is the correct way of finding the answer.
I've been given a question that I don't understand.
Question: Consider a test which rejects H0 if the number of observed successes is ≥r≥r , where r is some number. What is the smallest value of r that gives a test of size not exceeding 0.05?
We have been given:
o=50 ,for 50 observations
H0=p=1/2
I know that a test size is the probability of committing a type 1 error, where we falsely reject the null hypothesis when the null hypothesis is true. This happens 5% of the time if our p-value cut off is 0.05.
What I'm not sure about is : "What is the smallest value of r that gives a test of size not exceeding 0.05?"
Because if r is just some random number that hasn't been specified, what's stopping me from putting in a large number for r , such as 49?
I've attempted it by using:
mu=np
SD=sqrt(np(1−p))
a=0.05
Using RStudios for computation I did the following:
qnorm(0.95,mean=50*0.5,sd=sqrt(50*0.5*0.5)
But this gives me the test value. Because i'm unsure about what the question means, i'm not sure if this is the correct way of finding the answer.
